Category: Arithmetic
"Published in Newark, California, USA"
Find the missing digit so that it becomes divisible by 4 for
a. 5?627
b. 6721?
Solution:
a. Consider the given number
Since
the last two digit of a given number which is 27 is not a multiple of 4, then the
given number is not divisible by 4. There's nothing that we can do in
order to become divisible by 4 since the last digit of a given number is not a multiple of 4. You can assign any number to the missing digit but
still, the given number will never become divisible by 4.
b. Consider the given number
A number is divisible by 4 if the last two digit is a multiple of 4. Since 1 is located at the second to the last digit, then we can assign 2 and 6 to the last digit so that 1 becomes 12 and 16 which are the multiples of 4. Therefore, the possible numbers are 67212 and 67216.

This website will show the principles of solving Math problems in Arithmetic, Algebra, Plane Geometry, Solid Geometry, Analytic Geometry, Trigonometry, Differential Calculus, Integral Calculus, Statistics, Differential Equations, Physics, Mechanics, Strength of Materials, and Chemical Engineering Math that we are using anywhere in everyday life. This website is also about the derivation of common formulas and equations. (Founded on September 28, 2012 in Newark, California, USA)
Monday, May 26, 2014
Sunday, May 25, 2014
Finding Missing Digit - Divisibility Rule, 2
Category: Arithmetic
"Published in Newark, California, USA"
Find the missing digit so that it becomes divisible by 3 for
a. 35?83
b. 7895?
Solution:
a. Consider the given number
A number is divisible by 3 if the sum of the digits is a multiple of 3. If you add the rest of the digits, the sum will be equal to
Since 19 is not a multiple of 3, then we need to add a number so that it becomes a multiple of 3. So, 19 + 2 = 21. We can add also 5 (2 + 3) so that 19 + 5 = 24. We can add also 8 (2 + 3 + 3) so that 19 + 8 = 27. 8 is the highest digit that we can use because 8 + 3 = 11 will be a two digit number and we need to use only one digit to fill up the missing digit. Therefore, the possible numbers are 35283, 35583, and 35883.
b. Consider the given number
A number is divisible by 3 if the sum of the digits is a multiple of 3. If you add the rest of the digits, the sum will be equal to
Since 29 is not a multiple of 3, then we need to add a number so that it becomes a multiple of 3. So, 29 + 1 = 30. We can add also 4 (1 + 3) so that 29 + 4 = 33. We can add also 7 (1 + 3 + 3) so that 29 + 7 = 36. 7 is the highest digit that we can use because 7 + 3 = 10 will be a two digit number and we need to use only one digit to fill up the missing digit. Therefore, the possible numbers are 78951, 78954, and 78957.
"Published in Newark, California, USA"
Find the missing digit so that it becomes divisible by 3 for
a. 35?83
b. 7895?
Solution:
a. Consider the given number
A number is divisible by 3 if the sum of the digits is a multiple of 3. If you add the rest of the digits, the sum will be equal to
Since 19 is not a multiple of 3, then we need to add a number so that it becomes a multiple of 3. So, 19 + 2 = 21. We can add also 5 (2 + 3) so that 19 + 5 = 24. We can add also 8 (2 + 3 + 3) so that 19 + 8 = 27. 8 is the highest digit that we can use because 8 + 3 = 11 will be a two digit number and we need to use only one digit to fill up the missing digit. Therefore, the possible numbers are 35283, 35583, and 35883.
b. Consider the given number
A number is divisible by 3 if the sum of the digits is a multiple of 3. If you add the rest of the digits, the sum will be equal to
Since 29 is not a multiple of 3, then we need to add a number so that it becomes a multiple of 3. So, 29 + 1 = 30. We can add also 4 (1 + 3) so that 29 + 4 = 33. We can add also 7 (1 + 3 + 3) so that 29 + 7 = 36. 7 is the highest digit that we can use because 7 + 3 = 10 will be a two digit number and we need to use only one digit to fill up the missing digit. Therefore, the possible numbers are 78951, 78954, and 78957.
Saturday, May 24, 2014
Finding Missing Digit - Divisibility Rule
Category: Arithmetic
"Published in Vacaville, California, USA"
Find the missing digit so that it becomes divisible by 2 for
a. 245?7
b. 3259?
Solution:
a. Consider the given number
Since the last digit of a given number which is 7 is an odd number, then the given number is not divisible by 2. There's nothing that we can do in order to become divisible by 2 since the last digit of a given number is an odd number. You can assign any number to the missing digit but still, the given number will never become divisible by 2.
b. Consider the given number
The given number is divisible by 2 if the last digit is an even number. Since the missing digit is the last digit, then we can assign 0, 2, 4, 6, and 8 in order to become divisible by 2. Therefore, the possible numbers are 32590, 32592, 32594, 32596, and 32598.
"Published in Vacaville, California, USA"
Find the missing digit so that it becomes divisible by 2 for
a. 245?7
b. 3259?
Solution:
a. Consider the given number
Since the last digit of a given number which is 7 is an odd number, then the given number is not divisible by 2. There's nothing that we can do in order to become divisible by 2 since the last digit of a given number is an odd number. You can assign any number to the missing digit but still, the given number will never become divisible by 2.
b. Consider the given number
The given number is divisible by 2 if the last digit is an even number. Since the missing digit is the last digit, then we can assign 0, 2, 4, 6, and 8 in order to become divisible by 2. Therefore, the possible numbers are 32590, 32592, 32594, 32596, and 32598.
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