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Saturday, June 20, 2015

Dalton's Law of Partial Pressure, 4

Category: Chemical Engineering Math

"Published in Newark, California, USA"

A solvent-water mixture is to be distilled at 95°C. The vapor pressure of the solvent at this temperature is 130 mm Hg and that of water is 640 mm Hg. The solvent is immiscible in water and has a molecular weight of 150. What is the weight of the solvent in kilograms that will be carried over in the distillate with 200 kg of water?

Solution:

From the given word problem, it is about Dalton's Law of Partial Pressure because it involves the mixture of gas vapors which are solvent and water. In this problem, the molecular weight of a solvent is unknown but the partial pressure of solvent and water vapor are given. From the given partial pressures, we can solve for the mole fraction of a solvent vapor as follows





If W is the weight of a solvent and its molecular weight is 150 kg/kgmole, therefore the weight of a solvent that will be carried over in the distillate with 200 kg water is






Friday, June 19, 2015

Dalton's Law of Partial Pressure, 3

Category: Chemical Engineering Math

"Published in Newark, California, USA"

If ethanol and methanol are mixed 50/50 by weight at 60°C, and the solution assumed ideal, what is the composition of the vapor above the solution?

Solution:

From the given word problem, it is about Dalton's Law of Partial Pressure because it involves the mixture of gas vapors. Ethanol and methanol are mixed in equal proportion or amount. 

Basis: 100 grams of the mixture

Let's consider first the liquid phase. The number of moles of ethanol and methanol in the solution are
 
 

Next, consider the gas or vapor phase. From Saturated Vapor Pressure Data, the vapor pressure of pure ethanol at 60°C is 0.461395 atm and for the pure methanol is 0.832997 atm. Hence, the partial pressure of ethanol is






and the partial pressure of methanol is


 
 
 

Therefore, the % ethanol in the vapor is
 
 
 
 
 

and the % methanol in the vapor is
 
 

Thursday, June 18, 2015

Electrochemistry Problems, 3

Category: Chemical Engineering Math

"Published in Newark, California, USA"

An aqueous solution of gold nitrate is electrolyzed with a current of 0.555 amperes until 1.32 g of Au has been deposited on the cathode. If the atomic weight of Au is 197, determine the duration of the electrolysis.

Solution:

During the electrolysis process, gold (III) nitrate solution is ionized completely as follows


With the presence of electric current, gold is deposited on the cathode as follows


By using Faraday's Law of Electrolysis, we can solve for the time or duration of electrolysis of gold as follows


where:

        W = weight of a metal formed during electrolysis
        EW = equivalence weight of a metal 
        I = current or rate of flow of electrons
        t = time or duration of electrolysis

Therefore, the time or duration of electrolysis of gold is




                          or 


Note: In electroplating industries and jewelry industries, they are using the principles of electrolysis in coating a metal with another metal. A metal to be coated acts as a cathode and another metal used in coating acts as an anode in electrolysis.