Free counters!

Friday, November 30, 2012

Proving Two Parallel Lines - Circles

Category: Plane Geometry

"Published in Newark, California, USA"

If two circles are tangent externally and a line is drawn through a point of contact and terminated by the circles. Prove that the radii drawn to its extremities are parallel.

Photo by Math Principles in Everyday Life
Solution:

Consider the given figure


Photo by Math Principles in Everyday Life

Proof:

1. Statement: ∠1 ≅ ∠2
    
    Reason: Vertical angles are congruent.

2. Statement: OP OA and O'P O'B
    
    Reason: All points in a circle are equidistant from its center.

3. Statement: AB is drawn through point P.
    
    Reason: Given item.

4. Statement: ΔOAP and ΔO'PB are isosceles triangles.

    Reason: An inscribed triangle in a circle which consist of a center of a circle and the two end points of a chord is always an isosceles triangle.

5. Statement: ∠1 ≅ ∠3 and ∠2 ≅ ∠4

    Reason: The two opposite angles of an isosceles triangle are congruent.

6. Statement: ∠1 ≅ ∠2 ≅ ∠3 ≅ ∠4

    Reason: Transitive property of congruence.

7. Statement: ∠AOP = 180º - (∠1 + ∠3)
                      ∠PO'B = 180º - (∠2 + ∠4)

    Reason: The sum of the interior angles of a triangle is 180º.

8. Statement: ∠AOP ≅ ∠PO'B

    Reason: By computation at #7, if ∠1 ≅ ∠2 ≅ ∠3 ≅ ∠4, then ∠AOP ≅ ∠PO'B.

9. Statement: OA ║ O'B

    Reason: If a transveral line (OO') passed the two alternating interior angles (∠AOP and ∠PO'B) that are congruent, then it follows that the two lines (OA and O'B) which are adjacent to the alternating interior angles are parallel. 

    

Thursday, November 29, 2012

Money - Investment Problem

Category: Algebra

"Published in Newark, California, USA"

Mr. Manalang has 3 children who are entering college. He was offered to pay 75% of the tuition fee for the second and 50% for the third if he enrolls his 3 children in the same school. If the total tuition fee amounts to ₱ 4,500.00, how much is the regular tuition fee? 

Solution:

The above problem statement involves the money problem. Let's analyze the whole statements carefully as follows.

Let x be the amount of tuition fee for Mr. Manalang's 1st child.

Let 0.75 x be the amount of tuition fee for Mr. Manalang's 2nd child.

Let 0.50 x be the amount of tuition fee for Mr. Manalang's 3rd child.

If you add all the tuition fees of Mr. Manalang's children, the total amount is ₱ 4,500.00. The working equation for this problem will be

                      x + 0.75 x + 0.50 x = 4,500

                                         2.25 x = 4,500

                                                 x = 2,000

Therefore, the regular tuition fee is ₱ 2,000.00. This is also the tuition fee for Mr. Manalang's 1st child. 

Note: The monetary sign, ₱, is Philippine Pesos. The given word problem was in 1964. 


Wednesday, November 28, 2012

Quadratic Formula Derivation

Category: Algebra

"Published in Newark, California, USA"

Given the quadratic equation in general form:

                          
Prove that the Quadratic Formula has a formula of 



Solution:

There are three ways in solving the quadratic equation. First,  you can solve the quadratic equation by factoring. Second, if you cannot factor the quadratic equation, you can solve it by completing the square. Third, you can solve the quadratic equation by using the Quadratic Formula. Right now, we will derive the formula for Quadratic Formula. Let's consider the quadratic equation in general form



Divide both sides of the equation by the coefficient of x2 which is a. 



Transpose the third term to the right side of the equation



Apply the completing the square method to the above equation





Get the LCD at the right side of the equation



Take the square root on both sides of the equation







Therefore,