Free counters!

Thursday, November 29, 2012

Money - Investment Problem

Category: Algebra

"Published in Newark, California, USA"

Mr. Manalang has 3 children who are entering college. He was offered to pay 75% of the tuition fee for the second and 50% for the third if he enrolls his 3 children in the same school. If the total tuition fee amounts to ₱ 4,500.00, how much is the regular tuition fee? 

Solution:

The above problem statement involves the money problem. Let's analyze the whole statements carefully as follows.

Let x be the amount of tuition fee for Mr. Manalang's 1st child.

Let 0.75 x be the amount of tuition fee for Mr. Manalang's 2nd child.

Let 0.50 x be the amount of tuition fee for Mr. Manalang's 3rd child.

If you add all the tuition fees of Mr. Manalang's children, the total amount is ₱ 4,500.00. The working equation for this problem will be

                      x + 0.75 x + 0.50 x = 4,500

                                         2.25 x = 4,500

                                                 x = 2,000

Therefore, the regular tuition fee is ₱ 2,000.00. This is also the tuition fee for Mr. Manalang's 1st child. 

Note: The monetary sign, ₱, is Philippine Pesos. The given word problem was in 1964.