Category: Algebra
"Published in Newark, California, USA"
Mr. Manalang has 3 children who are entering college. He was offered to pay 75% of the tuition fee for the second and 50% for the third if he enrolls his 3 children in the same school. If the total tuition fee amounts to ₱ 4,500.00, how much is the regular tuition fee?
Solution:
The above problem statement involves the money problem. Let's analyze the whole statements carefully as follows.
Let x be the amount of tuition fee for Mr. Manalang's 1st child.
Let 0.75 x be the amount of tuition fee for Mr. Manalang's 2nd child.
Let 0.50 x be the amount of tuition fee for Mr. Manalang's 3rd child.
If you add all the tuition fees of Mr. Manalang's children, the total amount is ₱ 4,500.00. The working equation for this problem will be
x + 0.75 x + 0.50 x = 4,500
2.25 x = 4,500
x = 2,000
Therefore, the regular tuition fee is ₱ 2,000.00. This is also the tuition fee for Mr. Manalang's 1st child.
Note: The monetary sign, ₱, is Philippine Pesos. The given word problem was in 1964.