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Saturday, December 8, 2012

Integration Procedure - Parts

Category: Integral Calculus

"Published in Newark, California, USA"

Find the integral for


As you notice that there are two functions in the given equation but there's no differentials for the two functions. In this case, we have to use the integration procedure which is Integration by Parts. 


By using Integration by Parts,

Substitute the values of u, v, du, and dv to the above equation