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Monday, September 2, 2013

Derivative - Inverse Trigonometric Functions, 2

Category: Differential Calculus, Trigonometry

"Published in Suisun City, California, USA"

Prove that


Solution:

Consider the given equation above


Let


Take cosine on both sides of the equation, we have



Take the derivative on both sides of the equation with respect to x, we have








Next, we need to eliminate sin y in the equation. We know that 


but


Hence, the above equation becomes





Finally, the equation becomes



but


Therefore,