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Tuesday, September 3, 2013

Derivative - Inverse Trigonometric Functions, 3

Category: Differential Calculus, Trigonometry

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Prove that


Solution:

Consider the given equation above


Let


Take tangent on both sides of the equation, we have


Take the derivative on both sides of the equation with respect to x, we have 




Next, we need to eliminate sec2 y in the equation. We know that  


but


Hence, the above equation becomes



Finally, the equation becomes



but


Therefore,