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Sunday, August 17, 2014

Triangular Prism Problems, 4

Category: Solid Geometry

"Published in Vacaville, California, USA"

The trough shown in the figure has triangular ends which lie in parallel planes. The top of the trough is a horizontal rectangle 20 in. by 33 in., and the depth of the trough is 16 in. 

(a) How many gallons of water will it hold? (One gal. = 231 cu. in.)
(b) How many gallons does it contain when the depth of the water is 10 in.?
(c) What is the depth of the water when the trough contains 3 gals.?
(d) Find the wetted surface when the depth of the water is 9 in.

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Solution:

(a) Consider the given figure above

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The area of the base is




Therefore, the volume of a trough when filled with water which is the volume of a prism is




The volume of a trough in gallons is





(b) Consider the front side of a trough


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Bu using similar triangles, the area of the base with water is











Therefore, the volume of a trough with water is







The volume of a trough with water in gallons is







(c) The volume of a trough with water in cubic inches is







The area of the base of a trough with water is







By using similar triangles

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Therefore, the depth of water in a trough is













(d) Consider the front side of a trough


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By using similar triangles, the length of the base is







Let's assume that the base of a trough is an isosceles triangle.

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By using Pythagorean Theorem, the length of the wetted edge is














The area of the wetted base of a trough is




The lateral area of the wetted surface of a trough is





Therefore, the total area of the wetted surface of a trough is