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Monday, November 10, 2014

Solving Quadratic Equations of Two Unknowns, 6

Category: Algebra

"Published in Newark, California, USA"

Solve the following systems by elimination:



Solution:

Consider the given equations above



Did you notice that x², y², and -3y will be cancelled if you change the sign of the second equation and then perform the addition with the first equation? Well, if that's the case, we can solve for the value of x as follows
 

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Substitute the value of x to either of the two equations in order to get the value of y, we have






If you equate each factor to zero, then the values of y are 0 and 3.

Therefore, the solutions of the two equations are: