Category: Algebra
"Published in Newark, California, USA"
Find a 2-digit number whose ten's digit is 3 more than the unit's digit. The sum of the 2 digits is 7.
Solution:
Well, the given word problem is about a number problem where you will find the value of ten's and one's digits. Let's analyze the word problem as follows
Let x = value of one's digit
x + 3 = value of ten's digit
From the word statement, "the sum of the 2 digits is 7", the working equation for the given problem is
x + x + 3 = 7
2x + 3 = 7
2x = 7 - 3
2x = 4
x = 2
One's digit = x = 2
Ten's digit = x + 3 = 2 + 3 = 5
Therefore, the number is 52. The sum of the digits is 5 + 2 = 7 which is correct.
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