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Wednesday, April 24, 2013

Inspecting Integrating Factors

Category: Differential Equations, Integral Calculus, Algebra

"Published in Newark, California, USA"

Find the general solution for


Consider the given equation above

Expand the above equation and regroup as follows

Divide both sides of the equation by y2, we have

The grouped terms in parenthesis can be simplified as an exact differential as follows

Integrate on both sides of the equation, we have

Multiply both sides of the equation by y, we have

Therefore, the final answer is