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Saturday, August 3, 2013

Derivative - Trigonometric Functions, 3

Category: Differential Calculus, Trigonometry

"Published in Suisun City, California, USA"

Prove that


Solution:

Consider the above equation


Rewrite the left side of the equation as a quotient of two trigonometric functions as follows


Take the derivative of the above equation using the quotient of the two functions formula, we have





But


Hence, the above equation becomes




Therefore,