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Wednesday, August 7, 2013

Derivative - Trigonometric Functions, 5

Category: Differential Calculus, Trigonometry

"Published in Newark, California, USA"

Prove that


Solution:

Consider the given equation above


Rewrite the left side of the equation as a quotient of two trigonometric functions as follows


Take the derivative of the above equation using the quotient of the two functions formula, we have  








Therefore,