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Friday, August 9, 2013

Derivative - Trigonometric Functions, 6

Category: Differential Calculus, Trigonometry

"Published in Suisun City, California, USA"

 Prove that



Solution:

Consider the given equation above



Rewrite the left side of the equation as a quotient of two trigonometric functions as follows


Take the derivative of the above equation using the quotient of the two functions formula, we have  








Therefore,