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Saturday, February 23, 2013

Differentiation - Rate Problem

Category: Differential Calculus, Plane Geometry, Trigonometry

"Published in Newark, California, USA"

Each of two sides of a triangle are increasing at the rate of ½ foot per second, and the included angle is decreasing at 2° per second. Find the rate of change of the area when the sides and included angle are respectively 5 feet, 8 feet, and 60°.

Solution:

To illustrate the problem, it is better to draw the figure as follows


Photo by Math Principles in Everyday Life

From Plane Geometry, the area of a triangle is given by the formula



From Trigonometry, we know that





Therefore,





Take the derivative on both sides of the equation with respect to time, we have





but   b = 8 feet
        c = 5 feet
        θ = 60°
        db/dt = dc/dt½ ft/sec
        dθ/dt = - 2°/sec (negative because decreases)
                = (- 2°/sec) x (π/180°) = - π/90 radians/sec

Substitute the values to the above equation, we have








Therefore,





Since the rate is positive, then the area is increasing.