Free counters!

Thursday, February 21, 2013

Newtons Law - Cooling, 2

Category: Chemical Engineering Math, Differential Equations, Algebra

"Published in Newark, California, USA"

The body of a murder victim was discovered at 11:00 pm. At 11:30 pm, the victim's body temperature was measured to be 94.6 °F. After 1 hour, the body temperature was 93.4 °F. The room where the body was found at a constant temperature of 70 °F. Assuming that Newton's Law of Cooling is applicable and assuming that the normal human body temperature is 37 °C, determine the time of death.

Solution:

This is a great application of Newton's Law of Cooling. Mostly the Federal Bureau of Investigation (FBI) and the police officers in United States of America are using this method to calculate the time of a death or murder. Even in other countries like Philippines, Canada, Mexico, Japan, Italy, China, and so on are using this method, too. Let's analyze the given word problem as follows

Let u = be the temperature of a dead body
      t = be the time of death
      k = constant of cooling/heating

According to Newton's Law, the time rate of change of temperature is proportional to the temperature difference. 
 
      
The value of k is negative because it is a cooling process. When k is positive, then it is a heating process. The temperature of the surrounding is always a constant which is 70 °F. Solve for the general solution of the above equation, we have
 
     
Integrate on both sides of the equation
 
 
       
Take the inverse natural logarithm on both sides of the equation
 
 
       
but eC is still a constant. The above equation becomes
 

       
To solve for the values of k and C, we need to get the values of the limits as follows

If u1 = 94.6 °F, then t1 = 0 (measured at 11:30 pm)
   u2 = 93.4 °F, then t2 = 1.0 hr (measured at 12:30 am)

Substitute the first limit to the above equation to solve for the value of C
 
 
 
 
Therefore,
 


Substitute the second limit to the above equation to solve for the value of k
 



 
Take natural logarithm on both sides of the equation



Therefore,
 
   
Next, we need to use the normal temperature of a body (u = 37 °C = 98.6 °F) in order to calculate the time of death of a person as follows
    



   
Take natural logarithm on both sides of the equation
             

              
or

Since the value of time is negative, then we have to subtract it from the time where a dead body was first measured, which is at 11:30 pm, as follows

         11:30        ------>  11:30:00    ------->   11:29:60
         - 3:00:48              - 3:00:48                - 3:00:48
                                                                ---------------
                                                                     8:29:12

Therefore, a person is dead at 8:29:12 pm.