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Monday, February 4, 2013

Intersection - Line, Parabola

Category: Analytic Geometry, Algebra

"Published in Suisun City, California, USA"

Find the coordinates of the points of intersection for





Solution:

To illustrate the problem, let's draw the graph of the two given equations above.

For parabola, we need to reduce into standard form as follows





The center of parabola is C(0, -2) with vertex V(0, -1¾), and the ends of the latus rectum L1(½, 0) and L2(-½, 0). The curve of a parabola opens upward because x2 is positive.

For a line, we need to express into slope-intercept form as follows





The slope of a line is 2 and the y-intercept is 1. 

From the detailed information of a parabola and a line, we can sketch the graphs as follows


Photo by Math Principles in Everyday Life

As you can see that there are two points of intersection for a parabola and a line. To get the coordinates of their points of intersection, let's solve for the systems of the given two equations as follows




Change the sign of the second equation and then proceed with the addition as follows









Equate each factor to zero and solve for the value of x

For  x - 3 = 0                                              For  x + 1 = 0            
            x = 3                                                           x = -1

Next, substitute the values of x to either one of the given two equations in order to get the value of y. In this case, we will use the equation of a line so that it is easier to get the value of y as follows

If x = 3, then y will be







If x = -1, then y will be







Therefore, their points of intersection are P1(3, 7) and P2(-1, -1)