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Sunday, October 26, 2014

Graph of the System of Inequalities, 4

Category: Analytic Geometry

"Published in Vacaville, California, USA"

Graph the solution of the system of inequalities and find the coordinates of all vertices for

a. y < 9 - x²
    y ≥ x + 3

b. + y² ≤ 4
    x - y > 0

Solution:

a. For y < 9 - x², the given equation is a parabola that concave downward whose vertex is V(0, 9). Since the sign of inequality is less than, then all points along the curve are not included in the solution. If x = 0 and y = 0, then the given equation reduces to 0 < 9 which is correct and that point is included in the solution.

For y ≥ x + 3, the given equation is already written into slope-intercept form. Since the sign of inequality is greater than or equal to, then all points along the line are included in the solution. If x = 0 and y = 0, then the given equation reduces to 0 ≥ 3 which is correct and that point is included in the solution. Therefore, the graph of a pair of inequalities is

Photo by Math Principles in Everyday Life

The vertices of the graph are (-3, 0) and (2, 5) that are located at the intersection of the two shaded regions bounded by a line and a parabola. They are also included in the solution.

b. For x² + y² ≤ 4, the given equation is a circle whose center is C(0, 0) and radius is 2. Since the sign of inequality is less than or equal to, then all points along the curve are included in the solution. If x = 0 and y = 0, then the given equation reduces to 0 ≤ 4 which is correct and that point is included in the solution.

For x - y > 0, the given equation is already written into slope-intercept form. Since the sign of inequality is greater than, then all points along the line are not included in the solution. If x = 0 and y = 0, then the given equation reduces to 0 > 0 which is not correct and that point is not included in the solution. Therefore, the graph of a pair of inequalities is
 

Photo by Math Principles in Everyday Life

The vertices of the graph which are points A and B that are located at the intersection of the two shaded regions bounded by a line and a circle are also included in the solution.