"Published in Newark, California, USA"
A coin is placed beneath a rectangular slab of glass 5.0 m thick. If the index of refraction of the glass is 1.500, how far beneath the upper surface of the glass will the coin appear to be when viewed vertically from above?
Solution:
The given problem is about the refraction of light in which the incident ray and refracted ray are coincide with the normal line. To illustrate the problem, it is better to draw the figure as follows
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| Photo by Math Principles in Everyday Life |
Since the index of refraction of a glass is already given in the problem which is n = 1.500, therefore, the apparent depth of a coin from the upper surface of a glass is
